Distribution of two suits in two hidden hands
Column a: The number of cards in two suits in the 2 hidden handsColumn b: The probability that both suits divide evenly
Column c: The probability that at least one suit will divide evenly
If you have two suits and in both you are missing 8 cards
the probability that both suits will divide evenly is 11.87%
the probability that at least one suit will divide evenly is 53.57%
| a | b | c |
| 8-8 | 11.87% | 53.57% |
| 8-7 | 21.77% | 73.13% |
| 8-6 | 12.44% | 55.81% |
| 8-5 | 23.10% | 77.45% |
| 8-4 | 13.86% | 59.56% |
| 7-7 | 40.42% | 83.93% |
| 7-6 | 23.10% | 74.60% |
| 7-5 | 43.31% | 86.69% |
| 7-4 | 25.99% | 76.88% |
| 6-6 | 13.20% | 57.87% |
| 6-5 | 24.75% | 78.61% |
| 6-4 | 14.85% | 61.37% |
| 5-5 | 46.75% | 88.90% |
| 5-4 | 28.05% | 80.47% |
| 5-3 | 53.29% | 92.53% |
Source:
The official encyclopedia of bridge
Memphis Tennessee
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